Given: ABC is an Isosceles triangle with AB = AC. BD bisects ∠B and CE bisects ∠C
To find whether BD = CE or not!
AB=AC (Given)
hence, ∠B=∠C (Isosceles triangle property) (I)
12∠B=12∠C
∠DBC=∠ECB (II) (BD bisects ∠B and CE bisects ∠C)
Now, In △BDC and △FBC
BC=BC (Common)
∠C=∠B (From I)
∠DBC=∠ECB (From II)
Thus, △BDC≅△CFB (ASA rule)
Hence, BD=CE (By cpct)