is the cubic polynomial whose zeroes are 2, - 3 and 4.
A
x3−3x2−10x+24
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B
x3−x2−x+2
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C
x3+x2+x
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Solution
The correct option is Ax3−3x2−10x+24 If a, b and c are the zeroes of a cubic polynomial f(x), then f(x)=x3−(a+b+c)x2+(ab+bc+ca)x−(abc)
Thus, the required polynomial is: x3−(3)x2+(−10)x−(−24) =x3−3x2−10x+24