Question

Is the electric field due to a charge configuration with total charge zero necessarily?
Justify?

Answer 1

Dear student

Electric field due a charge in closed surface (ds) is given by gauss law as,
$$\begin{gathered} \int \overrightarrow{E}.d\overrightarrow{s}=\frac{q_{enclosed}}{{\epsilon }_0} \\ \mathrm{If}{q}_{enclosed}=0 \\ \Rightarrow E=0 \end{gathered}$$