Question

Is the following number a perfect cube?
$128$
Say yes or no.

• A. Yes
• B. No
• C. Ambiguous
• D. Data insufficient
  

Answer 1

The correct option is B No

Prime factorising $128$, we get,

$128=2\times 2\times 2\times 2\times 2\times 2\times 2=2^7$.

We know, a perfect cube has multiples of $3$ as powers of prime factors.

Here, number of $2$'s is $7$, which is not a multiple of $3$.

Hence, the given number $128$ is not a perfect cube.

Therefore, option $B$ is correct.