Question

Is the following statement correct?

Mass percentage of a solution containing 10g of solute in 100g of water is 10%.

Answer 1

Step 1: Given:

Mass of the solute$=10\mathrm{g}$

Mass of solvent $=100\mathrm{g}$

Step 2: Formula:

$\mathrm{Mass}\mathrm{percentage}\mathrm{of}\mathrm{a}\mathrm{solution}=\frac{\mathrm{Mass}\mathrm{of}\mathrm{the}\mathrm{solute}}{\mathrm{Mass}\mathrm{of}\mathrm{the}\mathrm{solution}}\times 100$

$\mathrm{Mass}\mathrm{of}\mathrm{solution}=\mathrm{Mass}\mathrm{of}\mathrm{solute}+\mathrm{Mass}\mathrm{of}\mathrm{solvent}$

Step 3: Finding the concentration of the solution:

$\mathrm{Mass}\mathrm{of}\mathrm{solution}=\mathrm{Mass}\mathrm{of}\mathrm{solute}+\mathrm{Mass}\mathrm{of}\mathrm{solvent}$

$=10\mathrm{g}+100\mathrm{g}$

$\mathrm{Mass}\mathrm{of}\mathrm{the}\mathrm{solution}=110\mathrm{g}$

$$\begin{gathered} \mathrm{Mass}\mathrm{percentage}\mathrm{of}\mathrm{a}\mathrm{solution}=\frac{\mathrm{Mass}\mathrm{of}\mathrm{the}\mathrm{solute}}{\mathrm{Mass}\mathrm{of}\mathrm{the}\mathrm{solution}}\times 100 \\ =\frac{10}{110}\times 100 \\ \mathrm{Mass}\mathrm{percentage}\mathrm{of}\mathrm{a}\mathrm{solution}=9.09\% \end{gathered}$$

Thus, the mass percentage of a solution containing $10\mathrm{g}$ of solute in $100\mathrm{g}$ of water is $9.09\%$.

Hence, the given statement is incorrect.