Question

Is the given sequence an AP? If it forms an AP, find the common difference $d$ and write the next three terms.
$0,-4,-8,-12$....

Answer 1

Common difference is equal to the difference between two consecutive terms

$-4-\left(0\right)=-4$

$-8-(-4)=-4$

$-12-(-8)=-4$

Since the difference between two consecutive terms is constant which is equal to $-4$

Therefore, the given sequence is in A.P.

Next term $=$ previous term $+$ common difference

$-12+(-4)=-16$

$-16+(-4)=-20$

$-20+(-4)=-24$