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Question

Is the line (-2,3)and (4,1) perpendicular to the line 3x = y+1 ? Does the line​3x= y+1 bisect the join of​(-2,3)and (4,1) ?

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Solution

Slope of the line l1 joining (x1,y1)=(-2,3) and (x2,y2)= (4,1) is given by m1 =y2-y1x2-x1=1-34+2=-26=-13Now the equation of the second line l2 is 3x=y+1 y=3x-1 By comparing with it with y=m2x+c we get m2=3Now since m1m2=-13×3 =-1 Hence product of slope of lines l1and l2 is -1 , so both lines are perpendicular.Now for the another part of question Mid point of line l1 joining (x1,y1)=(-2,3) and (x2,y2)= (4,1) is given by P=x2+x12,y2+y12=-2+42,1+32=(1,2)Now second line l2 : 3x=y+1 is satisfied by the point P (1,2) ,because 3×1=2+1 ,So the mid point of line l1 lies on the line l2 : 3x=y+1 . Hence line 3x=y+1 bisect The the line l1 joining (x1,y1)=(-2,3) and (x2,y2)= (4,1).

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