is the ratio of hydrogen and oxygen liberated at the electrodes during electrolysis of acidified water.

1:2

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2:1

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1:1

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Solution

The correct option is B 2:1
As per the balanced electrolytic reaction, for every two molecules of water- two molecules of $H_{2}$ gas and one molecule of $O_{2}$ gas is liberated.

$2 H_{2} O (l) d i l . H_{2} S O_{4} - ---- \to 2 H_{2} (g) + O_{2} (g)$

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Copy and complete the following sentences ?

With platinum electrodes hydrogen is liberated at the ........... and oxygen at the .......... during the electrolysis of acidified water.

H_{2}

O_{2}

5.6 l

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