is the smallest number which leaves 3 as remainder when divided by 25 and 20 separately.
A
50
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B
100
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C
150
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D
103
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Solution
The correct option is D 103 Using ladder diagram,
LCM of 20 and 25 is 2×2×5×5=100 100 is the smallest number which is divisible by both 25 and 20.
Now to find the number that leaves remainder 3 when divided by both 20 and 25, we add 3 to the LCM of 20 and 25. ∴103 is the smallest number which leaves 3 as the remainder when divided by 20 and 25 separately.