CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

is the smallest number which leaves 3 as remainder when divided by 25 and 20 separately.

A
50
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
100
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
150
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
103
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 103
Using ladder diagram,
LCM of 20 and 25 is 2×2×5×5=100
100 is the smallest number which is divisible by both 25 and 20.

Now to find the number that leaves remainder 3 when divided by both 20 and 25, we add 3 to the LCM of 20 and 25.
103 is the smallest number which leaves 3 as the remainder when divided by 20 and 25 separately.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Ladder Diagram
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon