Question

Is the work done in an open vessel at $300K$, when $56$ g iron reacts with dilute $HCI$ is?

• A. $600cal$
• B. $300cal$
• C. $150cal$
• D. $100cal$

Answer 1

Answer: (A)

$600cal$

We know that Molar mass of $Fe=56$ and $R=2ca{l}^{-1}Kmo{l}^{-1}$
$W=P\times \left(\frac{nRT}{P}\right)$ $n=\frac{56}{56}=1$
$=1\times 2\times 300$

$=600calorie.$