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Question

Is (x2y2) an odd number?
(I) x and y are integers.
(II) x+y is an odd number

A
Statement (I) ALONE is sufficient, but statement (II) alone is not sufficient
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B
Statement (II) ALONE is sufficient, but statement (I) alone is not sufficient
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C
BOTH statements TOGETHER are sufficient, but NEITHER statement alone is sufficient
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D
EACH statement ALONE is sufficient
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Solution

The correct option is B Statement (II) ALONE is sufficient, but statement (I) alone is not sufficient
From I, we cannot say that (x2y2)(x2−y2) is odd or even. Statement (II) x+y⇒x+y is odd x⇒x is even and y is odd or vice versa.
xy⇒x−y is odd (x2y2)⇒(x2−y2) is odd.

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