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Question

Is (x2y2) an odd number?
(I) x and y are integers
(II) x+y is an odd number.

A
Statement (I) alone is sufficient, but statement (II) alone is not sufficient.
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B
Statement (II) alone is sufficient, but statement (I) alone is not sufficient.
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C
Both statements together are sufficient, but neither statement alone is sufficient.
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D
Each statement alone is sufficient.
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Solution

The correct option is B Statement (II) alone is sufficient, but statement (I) alone is not sufficient.
From I, we cannot say that (x2y2) is odd nor even.
Statement (II) x+y is odd x is even and y is odd or vice versa.
xy is odd (x2y2) is odd.

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