Step: Finding the solution of equation x2−2x−15=0:
For x =5 to be solution of the given quadratic equation it should satisfy the given equation,
x2−2x−15=0
Substituting x =5 in the given equation,
We get,
L.H.S = (5)2−2(5)−15
=25 - 10 - 15
= 0
= R.H.S
Hence, x =5 is a solution of the given quadratic equation x2−2x−15=0