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Question

Is x=π2 is a solution of the equation:
2sin2x+sin22x=2

A
True
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B
False
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Solution

The correct option is A True
Solution must satisfy the equation, change putting x=π2 in equation
2sin2π2+sin22(π2) sinπ2=1
2sin2π2+sin2π sinπ=0
=2= RHS. TRUE


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