Is x3−4x2−x+1=(x−2)3 a quadratic equation?
Find whether the given equation is a quadratic or not :
⇒x3−4x2−x+1=(x−2)3⇒x3−4x2–x+1=x3–8–6x2+12x
Bringing all the like terms to one side of the equation, we get,
⇒x3–x3–4x2+6x2–x–12x+1+8=0
⇒2x2-13x+9=0
Thus the above equation is a polynomial of degree 2.
Hence, the given equation is a quadratic equation.
Check whether the following are quadratic equations :(i) (x+1)2=2(x−3)(ii) x2−2x=(−2)(3−x)(iii) (x−2)(x+1)=(x−1)(x+3)(iv) (x−3)(2x+1)=x(x+5)(v) (2x−1)(x−3)=(x+5)(x−1)(vi) x2+3x+1=(x−2)2(vii) (x+2)3=2x(x2−1)(viii) x3−4x2−x+1=(x−2)3