Isoelectronic species are:

C O, C N^{-}, N O^{+}, N_{2}, B F

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- C H_{3}, - ¨ N H_{2}, - ¨ O . . H, - ¨ F . . :

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C H_{2}, ¨ N H, ¨ O :

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All of the above

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Solution

The correct option is B All of the above
$N u m b e r o f t o t a l e l e c t r o n s . C O = 6 + 8 = 14, C N^{-} = 6 + 7 + 1 = 14, N O^{+} = 7 + 8 - 1 = 14, N_{2} = 14, B F = 5 + 9 = 14 C H_{3} = 6 + 3 = 9, N H_{2} = 7 + 2 = 9, O H = 8 + 1 = 9, F = 9 C H_{2} = 6 + 2 = 8, N H = 7 + 1 = 8, O = 8$

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Similar questions

C O, \to C H, \to ¨ N = C H_{2}, = ¨ O . ., \to {¨ O}^{\oplus}, = ¨ N H > ¨ N H

C O,

N O^{+},

O_{2}^{-},

C H_{4},

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N_{2}

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C H_{3} - C | C N H - + C H - C H_{3}

C | C N H_{2} - C H_{2} - + C H - C H_{3}

N_{2}, N_{2}^{\oplus}, N O^{\oplus}, N O^{⊖}, C O, C N^{⊖}, K O_{2}, N a_{2} O_{2}

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