Isomers of hexane, based on their branching, can be divided into three distinct classes as shown in the figure.
The correct order of their boiling point is:

I > I I > I I I

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I I I > I I > I

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I I > I I I > I

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I I I > I > I I

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Solution

The correct option is B $I I I > I I > I$
The correct order of their boiling point is $I I I > I I > I$
More the branching in an alkane, lesser will be the surface area, lesser will be the boiling point as weaker will be the intermolecular attractive forces.

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Similar questions

Isomers of hexane, based on their branching, can be divided into three distinct classes asshown below:

The correct order their boiling point is:

H_{3} C - C H | C H_{3} - C H_{3}

H_{3} C - C H_{3} | C | C H_{3} - C H_{3}

C H_{3} C H_{2} C H_{2} - C H_{3}

I . C_{9} H_{20} I I . C_{8} H_{18}

I I I . (C H_{3})_{2} C - (C H_{2})_{4} - C H_{3}

I V . C H_{3} - C H_{3} | C | C H_{3} - C H_{3} | C | C H_{3} - C H_{3}

C H_{3} C H_{2} C H_{2} C H_{2} O H

C H_{3} C H_{2} C H_{2} C H O

C H_{3} C H_{2} C H_{2} C O O H

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