Isomers of propanoic acid are:

H C O O C_{2} H_{5}

and

C H_{3} C O O C H_{3}

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H - C O O C_{2} H_{5}

and

C_{3} H_{7} C O O H

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C H_{3} C O O C H_{3}

and

C_{3} H_{7} O H

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C_{3} H_{7} O H

and

C H_{3} C O C H_{3}

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Solution

The correct option is A $H C O O C_{2} H_{5}$ and $C H_{3} C O O C H_{3}$
Propanoic acid: $C H_{3} C H_{2}$ Coon Meet formula $= C_{3} H_{6} o$
$(A) H c o o c_{2} H_{2}$ meet formula $= c_{3} H_{6} o_{2}$
$C H_{3} C o o c h_{3}$ Meet formula $= C_{3} H_{6} o_{2}$
Hence, option A is correct.
$(B) H - C o o c_{2} H_{5}$ and $C_{3} H_{7} c o o n$
$H C o o c_{2} H_{5}$ Meet formula $= C_{3} H_{6} O_{2}$
$C_{3} H_{4} C o o n$ meet formula $= C_{4} H_{8} O_{2}$
Hence, option B is incorrect.
Similarly, options C and D are incorrect.

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Similar questions

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C H_{3} O H

C_{2} H_{5} O H

C_{3} H_{7} O H

C_{3} H_{7} O H

Calculate the difference in the formulae and molecular masses for :

(a) $C H_{3} O H$ and $C_{2} H_{5} O H$

(b) $C_{2} H_{5} O H$ and $C_{3} H_{7} O H$

{CH}_{3} {COOCH}_{3} + (excess) C_{6} H_{5} MgBr H + \to x

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