Let us take 100 mL each of rubbing alcohol A and B,
% (v/v) = volume of solutevolume of solution×100
47% (v/v) means 47 mL isopropyl alcohol is present in 100 mL of the solution.
Volume of C3H8 in the sanitizer of company A = 47 mL
Mass of isopropyl alcohol in the sanitizer of company A
= volume×density
Mass of isopropyl alcohol,
=47×x=47x g
Similarly, volume of isopropyl in the sanitizer of company B = 23.5 mL.
Mass of isopropyl alcohol in the sanitizer of company B=
23.5×x=23.5x g
So, the ratio of mass of isopropyl alcohol present in sanitizer of company A and company B
=mass of isopropyl alcohol of company Amass of isopropyl alcohol of company B = 47x23.5x = 2:1