Isopropyl alcohol is heated with suspension of bleaching powder $(C a O {C l}_{2})$ with water. The products are:

ethane and propane

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ethyne and ethene

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trichloromethane and calcium acetate

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carbon tetrachloride

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Solution

The correct option is C trichloromethane and calcium acetate
$C a O C L_{2} + H_{2} O \to C l_{2} + C a (O H)_{2}$
Hence the answer is (c)

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