Question

Isopropyl chloride and ethyl chloride both react with $Na$ in presence of dry ether. How many products are obtained?

Answer 1

When any alkyl halide reacts with $Na$ in presence of dry ether, then free radical alkyl formed along with halide ion because $Na$ is a metal and provide a free electron.

$R-X+Na\underset{ether}{\overset{dry}{\to }}{R}^{\cdot }+C{l}^{-}$

Thus when isopropyl chloride & ethyl chloride both react with sodium the free radical formed are

(Refer to Image 1)

Maximum product which can form are

(Refer to Image 2)