It costs Rs 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If the cost of painting is at the rate of Rs 20 per m², find

(i) Inner curved surface area of the vessel

(ii) Radius of the base

(iii) Capacity of the vessel

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Solution

(i) Rs 20 is the cost of painting 1 m² area.

Rs 2200 is the cost of painting =

= 110 m² area

Therefore, the inner surface area of the vessel is 110 m².

(ii) Let the radius of the base of the vessel be r.

Height (h) of vessel = 10 m

Surface area = 2πrh = 110 m²

(iii) Volume of vessel = πr²h

= 96.25 m³

Therefore, the capacity of the vessel is 96.25 m³ or 96250 litres.

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Question 5 (i)
It costs Rs. 2200 to paint the inner curved surface of a cylindrical vessel of 10 m deep. If the cost of painting is at the rate of $R s 20 p e r m^{2}$ , find

(i) Inner curved surface area of the vessel.

$[A s s u m e π = \frac{22}{7}]$

It costs Rs. 2200 to paint the inner curved surface of a cylindrical vessel of 10 m deep. If the cost of painting is at the rate of $R s 20 p e r m^{2}$ , find the inner curved surface area of the vessel.

$[A s s u m e π = \frac{22}{7}]$

Question 5 (iii)
It costs Rs. 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If the cost of painting is at the rate of $R s 20 p e r m^{2}$ , find: