Question

It costs Rs. 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If the cost of painting is at the rate of $Rs20per{m}^2$, find the radius of the vessel.

• A. $1.75m$
• B. $4.75m$
• C. $3m$
• D. $3.5m$

Answer 1

The correct option is A

$1.75m$

Rs. 20 is the cost of painting $1m^2$ area.

Area painted for Rs. 2200 $=(\frac{1}{20}\times 2200)m^2$

$=110m^2$

Therefore, the inner surface area of the vessel is $110m^2$.

Let the radius of the base of the vessel be r.

Height (h) of the vessel = 10 m
Surface area $=2\pi rh=110m^2$

$\Rightarrow (2\times \frac{22}{7}\times r\times 10)m=110m^2$
$\Rightarrow r=\left(\frac{7}{4}m\right)=1.75m$