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Question

It ab+c=x,bc+a=y,ca+b=z, what is the value of 11+x+11+y+11+z ?

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Solution

1+x=1+ab+c=a+b+cb+c so 11+x=b+ca+b+c etc
Given expression =b+ca+b+c+c+aa+b+c+a+ba+b+c=2(a+b+c)a+b+c=2
=2(a+b+c)(a+b+c)=2

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