It experiences an increase in energy through a mechanical influence A 50 g bullet moving with a velocity of 10 $m s^{- 1}$ strikes a block of mass 950 g at rest and gets embedded in it. The percentage loss in kinetic energy is

100%

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95%

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50%

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Solution

The correct option is B 100%
initial kinetc energy is 1/2 × 50 × 10 ×10

final kinetic energy is 1/2 × 50 × final velocity^2

% loss is k.E = final K.E - initial k.E =100%

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Similar questions

A 50 g bullet moving with velocity 10 m/s strikes a block of mass 950 g at rest and gets embedded in it. The loss in kinetic energy will be

1950

50

{100 m s}^{- 1}

{m s}^{- 1}

g

K E

50 g m

10 m / s

950 g m

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