It is claimed that two cesium clocks, if allowed to run for $100$ years, free from any disturbance, may differ by only about $0.02 s$ . What does this imply for the accuracy of the standard cesium clock in measuring a time-interval of $1 s$ ?

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Solution

Errror in $100$ years $= 0.02 s$
Error in $1 s = \frac{0.02}{100 \times 365 \frac{1}{4} \times 24 \times 60 \times 60}$
$= 7.9 \times 10^{- 13} \approx 10^{- 12}$
Hence, the accuracy of standard caesium clock in measuring a time interval of $1 s$ is $10^{- 12}$

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It is claimed that two cesium clocks, if allowed to run for 100 years, free from any disturbance, may differ by only about 0.02s. What does this imply for the accuracy of the standard cesium clock in measuring a time-interval of 1s ?

Errror in 100 years =0.02sError in 1s=0.02100×36514×24×60×60=7.9×10−13≈10−12Hence, the accuracy of standard caesium clock in measuring a time interval of 1s is 10−12

It is claimed that two cesium clocks, if allowed to run for $100$ years, free from any disturbance, may differ by only about $0.02 s$ . What does this imply for the accuracy of the standard cesium clock in measuring a time-interval of $1 s$ ?

Errror in $100$ years $= 0.02 s$
Error in $1 s = \frac{0.02}{100 \times 365 \frac{1}{4} \times 24 \times 60 \times 60}$
$= 7.9 \times 10^{- 13} \approx 10^{- 12}$
Hence, the accuracy of standard caesium clock in measuring a time interval of $1 s$ is $10^{- 12}$