1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Physics
Properties of Charges
It is found e...
Question
It is found experimentally that
13.6
eV energy required to separate a hydrogen atom into a proton and an electron.Calculate the velocity of the electron in hydrogen atom.
Open in App
Solution
E
=
K
E
+
P
E
=
13.6.
e
v
K
E
=
|
E
|
=
13.6
e
v
1
2
m
v
2
=
13.6
×
1.6
×
10
−
19
V
=
√
27.2
×
1.6
×
10
19
9.1
×
−
31
=
2.2
×
10
6
m
/
s
Suggest Corrections
1
Similar questions
Q.
The energy required to separate a hydrogen atom into a proton and an electron is 13.6eV. Then the velocity of electron in a hydrogen atom is
Q.
13.6
e
V
is needed for ionisation of a hydrogen atom. An electron in a hydrogen atom in its ground state absorbs
1.50
times as much energy as the minimum energy required for it to escape from the atom. What is the wavelength and velocity of the emitted electron?
Q.
The ionization potential of a hydrogen atom is
13.6
eV
. The energy required to remove an electron from the second orbit of a hydrogen atom is:
Q.
The I.E. of hydrogen atom is
13.6
eV. The energy required to remove an electron from
n
=
2
state of the hydrogen atom is:
Q.
The ionisation potential of hydrogen atom is 13.6 volt. The energy required to remove an electron in the n = 2 state of the hydrogen atom is
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Idea of Charge
PHYSICS
Watch in App
Explore more
Properties of Charges
Standard XII Physics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Solve
Textbooks
Question Papers
Install app