Question

It is found that the equilibrium constant increases by a factor of four when the temperature is increased from ${25}^{\circ }Cto{40}^{\circ }C$. The value of $\Delta H$ is

• A. 25.46 kJ
• B. 171.67 kJ
• C. 89.43 kJ
• D. 71.67 kJ

Answer 1

The correct option is D 71.67 kJ

$log\frac{4}{1}=\frac{\Delta H}{2.303R}\left(\frac{15}{298\times 313}\right)$
$\frac{8.30\times 0.6\times 2.303\times 298\times 314}{15}=\Delta H$
$\Delta H=71.57kJ$