It is found that A- - B- - A- - This necessarily implies-

The correct option is A B⃗ = 0 A⃗+ B⃗ = A⃗ Its mean B⃗ will have zero magnitude and there thave no direction. ...

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Vector Addition

It is found t...

Question

It is found that $\to A$ + $\to B$ = $\to A$ . This necessarily implies:

\to B

= 0

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\to A

\to B

are antiparallel

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\to A

\to B

are perpendicular

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\to A

\to B

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Similar questions

\to r \times \to a = \to b \times \to a; \to r \times \to b = \to a \times \to b; \to a \neq 0, \to b \neq 0, \to a \neq λ \to b; \to a

\to b

\to r =

| \to b | \to a + | \to a | \to b

| \to b | \to a - | \to a | \to b

| \to a | \to b + | \to b | \to a

| \to a | \to b - | \to b | \to a

\to a

\to b

| \to a | \to b + | \to b | \to a

| \to a | \to b - | \to b | \to a

\to a

\to b

\to a + \to b + \to c = 0

\to a \times \to b = \to b \times \to c = \to c \times \to a

\to a, \to b, \to c

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