It is given that -1 is one of the zeros of the polynomial x3+2x2−11x−12. Find all the zeros of the given polynomial.
One zero of the polynomial x3+2x2−11x−12 is -1
Therefore, x+1 is a factor of x3+2x2–11x–12
Dividing x3+2x2–11x–12 by x+1
Quotient q(x)=x2+x–12
=x2+4x–3x–12
=(x+4)(x–3)
Other zeros of given polynomial are the zeros of q(x)
Therefore, q(x)=0
⇒ (x+4)(x–3)=0
⇒ Either x+4=0 or x–3=0
⇒ Either x=−4 or x=3
Therefore, -4, 3 are the zeros of q(x)
Therefore, The zeros of given polynomial are -4, -1 and 3