It is given that 5 main scale division of a vernier caliper coincide with 6 vernier scale divisions. When jaws are closed zeros of both scale do not coincide and has a negative zero error. Find magnitude of this zero error in mm. 1 main scale division is equal to 1mm.

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Solution

L.C=1MSD-1VSD where 5 MSD = 6VSD

$L . C = 1 M S D - \frac{5}{6} M S D = \frac{1}{6} M S D = 0.167 m m$

zero error = $n \times L . C = 4 \times 0.167 = 0.64$

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It is given that 5 main scale division of a vernier caliper coincide with 6 vernier scale divisions. When jaws are closed zeros of both scale do not coincide and has a negative zero error. Find magnitude of this zero error in mm. 1 main scale division is equal to 1mm.

L.C=1MSD-1VSD where 5 MSD = 6VSD L.C=1MSD−56MSD=16MSD=0.167 mm zero error =n×L.C=4×0.167=0.64

L.C=1MSD-1VSD where 5 MSD = 6VSD

$L . C = 1 M S D - \frac{5}{6} M S D = \frac{1}{6} M S D = 0.167 m m$

zero error = $n \times L . C = 4 \times 0.167 = 0.64$