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Question
It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday ?
It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday ?
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Solution
Let E be the event of having the same birthday.
Given, the probability of 2 students not having the same birthday is 0.992
⇒ P(E') = 0.992
But P(E) + P(E') = 1
Therefore, P(E)= 1 - P(E') = 1-0.992 = 0.008
Let E be the event of having the same birthday.
Given, the probability of 2 students not having the same birthday is 0.992
⇒ P(E') = 0.992
But P(E) + P(E') = 1
Therefore, P(E)= 1 - P(E') = 1-0.992 = 0.008
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