It is given that k1=1500 N/m, k2=500 N/m, m1=2 kg and m2=1 kg. then, what is the total potential energy storedin the springs in equilibrium in Joule? (g=10m/s2)
A
0.3
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B
0.2
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C
0.4
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D
0.6
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Solution
The correct option is B0.4 Let the extensions of the springs with spring constants k1 and k2 be x1 and x2 respectively.
The forces acting on the body are as shown in the figure.
For equilibrium, k2x2=m2g k1x1=m1g+k2x2
Putting the values in the above equations, we get x2=0.02m and x1=0.02m
So the potential energy stored in the springs will be