The correct option is A 5
Let the zeros of the polynomial be a, b and c. Then,
p(x)=(x−a)(x−b)(x−c)
The constant term of the polynomial is abc=24.
Also, it is given that a, b and c, all are integers.
So, the zeroes of the polynomial are factors of 24. Possible zeroes are:
±1,±2,±3,±4,±6,±12,±24
Clearly, 5 is not a zero of the polynomial.