Question

It is known that a box of 100 electric bulbs contains 8 defeective bulbs. One bulb is taken out at random from the box. What is the probability that the bulb drawn is (i) defective ? (ii) non-defective?

Answer 1

$\text{In a box of 100 electric bulb, 8 are defective}\text{Then non-defective bulbs =100-8=92}\text{(i) Probability of a drawn bulb, which is defective}=\frac{8}{100}=\frac{2}{25}\text{(ii)Probability of a drawn bulb which is non-defective}=\frac{92}{100}=\frac{23}{25}$