It is known that a box of 100 electric bulbs contains 8 defeective bulbs. One bulb is taken out at random from the box. What is the probability that the bulb drawn is (i) defective ? (ii) non-defective?

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Solution

$In a box of 100 electric bulb, 8 are defective Then non-defective bulbs =100-8=92 (i) Probability of a drawn bulb, which is defective = \frac{8}{100} = \frac{2}{25} (ii)Probability of a drawn bulb which is non-defective = \frac{92}{100} = \frac{23}{25}$

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It is known that a box of 100 electric bulbs contains 8 defeective bulbs. One bulb is taken out at random from the box. What is the probability that the bulb drawn is (i) defective ? (ii) non-defective?

In a box of 100 electric bulb, 8 are defective Then non-defective bulbs =100-8=92 (i) Probability of a drawn bulb, which is defective=8100=225(ii)Probability of a drawn bulb which is non-defective=92100=2325

$In a box of 100 electric bulb, 8 are defective Then non-defective bulbs =100-8=92 (i) Probability of a drawn bulb, which is defective = \frac{8}{100} = \frac{2}{25} (ii)Probability of a drawn bulb which is non-defective = \frac{92}{100} = \frac{23}{25}$