14C6
Number of protons = 6 , mass of protons = 6 amu
Number of neutrons = 8, mass of neutrons = 8 amu
Mass of 14C6 = 6 + 8 = 14 amu
When mass of neutrons is halved and mass of protons is doubled, mass of 14C6becomes 8/2 + 6 x 2 = 16 amu
Percentage by which the mass has increased = (16-14)/14 x 100
= 14.28 %
Hence, mass of 14C6 is 14.28 % more