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It is known that the intensity of x - ray reduces exponentially when passed through any metal medium. If 1 cm of aluminium reduces x - ray intensity by factor of 10, then what thickness in cm is required if incident intensity is doubled to maintain same exit field intensity. [ln 10 = 2.3]


Solution

I=I0ektI010=I0 ekt   [t=1 cm]
ek=10ln 10=k=2.3
Again I010=2I0 ektekt=20

kt = ln 20 2.3 t= ln 2 + ln 10
2.3t=0.693+2.32.3(t1)=0.693

f=1.30

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