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Question

It is observed in a potentiometer experiment that no current passes through the galvanometer across when the terminals of a cell are connected across a certain length of the potentiometer wire. On shuting the cell by a 2 Ω resistance, the balancing length is reduced to half. The internal resistance of the cell is :-

A
4Ω
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B
2Ω
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C
1Ω
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D
8Ω
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Solution

The correct option is B 2Ω
If initial (un-shunted) balance length is μ, the shunted balance
length is l2=l1/2 against external resistance R=2Ω
so internal resistance :-
r=(ll21)R=(21)×2=2Ω

1106828_1179761_ans_7b220791a4764bbb890d852660ad4834.JPG

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