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The Photon Model

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Question

It is observed that photoelectron emission stops at a certain time t after the light source is switched on. It is due to the retarding potential developed in the metallic sphere due to left over positive charges. The stopping potential (V) can be represented as

A

2 (K E_{m a x} / e)

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B

(K E_{m a x} / e)

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C

(K E_{m a x} / 3 e)

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D

(K E_{m a x} / 2 e)

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Solution

The correct option is C $(K E_{m a x} / e)$
If total energy of the electron is zero, then the electron will not escape.
$K E_{m a x} - e V = 0$
$s o V = K E_{m a x} / e$

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