It is possible to calculate the value of - H for the reaction H2g - Br2l- 2HBrg from the bond enthalpy data alone-

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Difference between Internal Energy and Enthalpy

It is possibl...

Question

It is possible to calculate the value of $Δ H$ for the reaction
$H_{2} (g) + B r_{2} (l) ⟶ 2 H B r (g)$ from the bond enthalpy data alone.

yes

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Δ H

is a constant value.

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none

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25^{o} C

\frac{1}{2} H_{2} (g) + \frac{1}{2} O_{2} (g) \to O H (g); Δ H = 10.06 k c a l

H_{2} (g) \to 2 H (g); Δ H = 104.18 k c a l

O_{2} (g) \to 2 O (g); Δ H = 118.32 k c a l

O - H

O H

H_{2} (g) + B r_{2} (g) ⟶ 2 H B r (g); Δ H^{⊖} = - 72.40 k J

Δ G^{⊖} = - 106.49 k J, T = 298 K

Δ S

C (g r a p h i t e) + O_{2} (g) \to C O_{2} (g); Δ H = - 393.5 k J

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l); Δ H = - 286.2 k J

C_{2} H_{4} (g) + 3 O_{2} (g) \to 2 C O_{2} (g) + 2 H_{2} O (l); Δ H = - 1410.8 k J

H - H, B r - B r

H - B r

k J m o l^{- 1}

Δ H

H_{2 (g)} + B r_{2 (g)} \to 2 H B r_{(g)}

Δ H^{\circ}

Δ S^{\circ}

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