It is possible to measure the passage of $50$ electrons per second with a certain sensitive device. This corresponds to a current of :

8 \times 10^{- 18} A

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1.6 \times 10^{- 20} A

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8 \times 10^{- 20} A

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1.6 \times 10^{- 19} A

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Solution

The correct option is A $8 \times 10^{- 18} A$
Let number of electrons per second be n.
Given,
$e = 1.6 \times 10^{- 19} C$ , $n = 50$
The current is defined as rate of flow of charge,
$I = \frac{q}{t}$
Hence,
$I = n \times e$
Substituting values,
$I = 50 \times 1.6 \times 10^{- 19} = 8 \times 10^{- 18} A$

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It is possible to measure the passage of 50 electrons per second with a certain sensitive device. This corresponds to a current of :

The correct option is A 8×10−18ALet number of electrons per second be n.Given,e=1.6×10−19C , n=50The current is defined as rate of flow of charge,I=qt Hence,I=n×eSubstituting values,I=50×1.6×10−19=8×10−18A

It is possible to measure the passage of $50$ electrons per second with a certain sensitive device. This corresponds to a current of :