It is possible to project a particle with a given speed in two possible ways so that it has the same horizontal range. If time of flight in two cases are 3 s and 4 s, then speed of projection of the particle will be (1) 20 m/s (2) 25 m/s (3) 50 m/s (4) 15 m/s

Open in App

Solution

Suggest Corrections

Similar questions

Q. It is possible to project a particle with a given speed in two possible ways so that it has the same horizontal range

R

. The product of the times taken by it in the two possible ways is

It is possible to project a particle with a given speed in two possible ways so as to have the same range, R. The product of the times taken to reach this point in the two possible ways is proportional to

Q. It is possible to project a particle with a given velocity in two possible ways so as to make them pass through a point P at a horizontal distance

r

from the point of projection. If

t_{1}

and

t_{2}

are times taken to reach this point in two possible ways, then the product

t_{1} t_{2}

is proportional to:

Q. To obtain a given range of a projectile, there are two possible angles of projection with the horizontal. If

R

is the range for an angle of projection of

25^{o}

, then the other possible angle of projection is

Q. For a given velocity, a projectile has the same range

R

for two angles of projection. If

t_{1}

and

t_{2}

are the time of flight in the two cases, then:

Join BYJU'S Learning Program