It is required to construct a 10μF capacitor which can be connected across a 200V battery. Capacitors of capacitance 10μF are available but they can withstand only 50V Design a combination which can yield the desired result
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Solution
Let there are 'x' no of capacitors in series ie in a row
So, x×50=200
⇒x=4 capacitors
Effective capacitance in a row =104
Now, let there are 'y' such rows,
So, 104×y=10
⇒y=4 capacitor
So, the combinations of four rows each having 4 capacitors each will form a 10μF capacitor that can withstand 200V.