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Question

It is required to construct a 10microF capacitor which can be connected across a 200V battery.Capacitors of capacitance 10microF are available but they can withstand only 50V. Design a combination which can yield the desired result

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Solution

There is a 200V battery and each capacitor can withstand 50V.
so ,
we need 200/50=4 capacitors.
  • we know C is indirectly proportional to V. so if we increase the equivalent capacitance the V will decrease.

To increase C we connect them in parallel.

Ceq=10uF*4=40uF .

now we can connect it across 200V battery.

so,

Total 16 capacitor.. 4 rows.. Each row have 4 capacitor .

Thank you :)

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