Question

It is required to seat 5 men and 4 women in a row so that the women occupy the even places. How many such arrangements are possible?

Answer 1

$5$ MEN , $4$ WOMEN

number of ways of arranging women $=4!=24$ ways

number of ways of arranging men $=5$ places $=5$ men $=5!=120$ ways

Total number of ways

$\Rightarrow 24\times 120$

$\Rightarrow 2880$ Ways

Hence the correct answer is $2880$ Ways