The correct option is D x3y1z4
Jerry needs a like term of the 9x5y8z7.
Instead, he writes 2x8y9z11.
Jerry needs a term in which the powers of the variables are as follows:
x: 5
y: 8
z: 7
Let's assume that Jerry is dividing his written expression (2x8y9z11). Now, the obtained term is a like term of xaybzc.
2x8y9z11 ÷ xaybzc = 2x(8 – a)y(9 – b)z(11 – c)
Now, if the obtained term is a like term of 9x5y8z7, the exponents should be equal.
Hence,
8 – a = 5 --> a = 3
9 – b = 8 --> b = 1
11 – c = 7 --> c = 4
So, Jerry should divide his expression with x3y1z4