It takes time 8 min for light to reach from sun to the earth surface- If speed of light is taken to be 3 - 108 m s-1- find the order of magnitude of distance from the sun to the earth in km-

The correct option is C 10^8 km Time t=8 min=480 sec Speed of light c=3×10^8 ms^ 1 Distance=t× c=1.44×10^11m=1.44×10^8km So order of magnit ...

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Standard XII

Physics

Order of Magnitude

It takes time...

Question

It takes time $8$ min for light to reach from sun to the earth surface. If speed of light is taken to be $3 \times 10^{8}$ m $s^{- 1}$ , find the order of magnitude of distance from the sun to the earth in km.

10^{7} k m

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15 \times 10^{8} k m

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10^{8} k m

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10^{9} k m

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Solution

The correct option is C $10^{8} k m$
Time $t = 8 m i n = 480 s e c$
Speed of light $c = 3 \times 10^{8} m s^{- 1}$
$D i s t a n c e = t \times c = 1.44 \times 10^{11} m = 1.44 \times 10^{8} k m$
So order of magnitude os distance is $10^{8} k m$

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It takes time 8 min for light to reach from sun to the earth surface. If speed of light is taken to be 3×108 m s−1, find the order of magnitude of distance from the sun to the earth in km.

The correct option is C 108kmTime t=8 min=480 secSpeed of light c=3×108 ms−1Distance=t×c=1.44×1011m=1.44×108kmSo order of magnitude os distance is 108km

It takes time $8$ min for light to reach from sun to the earth surface. If speed of light is taken to be $3 \times 10^{8}$ m $s^{- 1}$ , find the order of magnitude of distance from the sun to the earth in km.

The correct option is C $10^{8} k m$
Time $t = 8 m i n = 480 s e c$
Speed of light $c = 3 \times 10^{8} m s^{- 1}$
$D i s t a n c e = t \times c = 1.44 \times 10^{11} m = 1.44 \times 10^{8} k m$
So order of magnitude os distance is $10^{8} k m$