It was found that an observation $8$ was incorrect, this is observation is now omitted. Find the new mean.

10

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10.105

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10.145

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16.25

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Solution

The correct option is A $10.105$
Mean $= 10 \Rightarrow \frac{\sum x_{i}}{20} = 10$
$∴ \sum x_{i} = 200$
So, correct mean $u^{'} = \frac{(\sum x_{i}) - 8}{19} = \frac{192}{19}$
Thus, $u^{'} = 10.105$ .
Ans-Option $B$ .

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The mean and standard deviation of 20 observation are found to be 10 and 2 respectively. On rechecking, it was found that an observation 8 was incorrect. Calculate the correct mean and standard deviation in each of the following cases :

(i) If wrong item is omitted

(ii) If it is replaced by 12.

The mean ans dtandard deviation of 20 observations are found to be 10 and 2 respectively. On rechecking it was found that an observation 8 was incorrect. Calculate the correct mean and standard deviation in each of the following cases :

(i) If worng item is omitted

(ii) If it is replaced by 12.

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It was found that an observation 8 was incorrect, this is observation is now omitted. Find the new mean.

The correct option is A 10.105Mean =10⇒∑xi20=10∴∑xi=200So, correct mean u′=(∑xi)−819=19219Thus, u′=10.105.Ans-Option B.

It was found that an observation $8$ was incorrect, this is observation is now omitted. Find the new mean.

The correct option is A $10.105$
Mean $= 10 \Rightarrow \frac{\sum x_{i}}{20} = 10$
$∴ \sum x_{i} = 200$
So, correct mean $u^{'} = \frac{(\sum x_{i}) - 8}{19} = \frac{192}{19}$
Thus, $u^{'} = 10.105$ .
Ans-Option $B$ .