IUPAC name of CH3(CH2)3CH3 is
Pentane
What should we do first?
Let's calculate the number of carbons present.
For that, let's write it in a clearer format using the bonds.
H−H|C|H−H|C|H−H|C|H−H|C|H−H|C|H−H
Now, five carbons are present
Only single bonds are present
Five carbon ⇒ root word → pent
single bonds ⇒ suffix → ane
Therefore, it is pentane.